C++/Python FEniCS/dolfinx@070a2cd

FEniCS · Nov 25, 2024 · 72ed5fa · 72ed5fa
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diff --git a/dolfinx/main/cpp/demos/demo_biharmonic.html b/dolfinx/main/cpp/demos/demo_biharmonic.html
@@ -136,8 +136,8 @@ <h3>Weak formulation<a class="headerlink" href="#weak-formulation" title="Link t
 \forall \ K \in \mathcal{T} \right\}
 \]</div>
 <p>and considering the boundary conditions</p>
-<div class="amsmath math notranslate nohighlight" id="equation-ca0d0919-485d-41c0-b383-3da742cf46d1">
-<span class="eqno">(1)<a class="headerlink" href="#equation-ca0d0919-485d-41c0-b383-3da742cf46d1" title="Permalink to this equation"></a></span>\[\begin{align}
+<div class="amsmath math notranslate nohighlight" id="equation-78e6b892-c5ef-4f28-8ba0-d6983c4926e1">
+<span class="eqno">(1)<a class="headerlink" href="#equation-78e6b892-c5ef-4f28-8ba0-d6983c4926e1" title="Permalink to this equation"></a></span>\[\begin{align}
 u &amp;= 0 \quad {\rm on} \ \partial\Omega, \\
 \nabla^{2} u &amp;= 0 \quad {\rm on} \ \partial\Omega,
 \end{align}\]</div>

diff --git a/...nx/main/python/_downloads/9561cf6cd1a70079b986f4eb31580cbd/demo_poisson_matrix_free.ipynb b/...nx/main/python/_downloads/9561cf6cd1a70079b986f4eb31580cbd/demo_poisson_matrix_free.ipynb
@@ -2,7 +2,7 @@
  "cells": [
   {
    "cell_type": "markdown",
-   "id": "2ee48f64",
+   "id": "c4d59a02",
    "metadata": {},
    "source": [
     "# Matrix-free conjugate gradient solver for the Poisson equation\n",
@@ -72,7 +72,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "c13a1fe0",
+   "id": "fa8546df",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -82,7 +82,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "52870c29",
+   "id": "fc66bb3a",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -92,7 +92,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "125737b5",
+   "id": "0df726e1",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -104,7 +104,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "05357257",
+   "id": "2f835469",
    "metadata": {},
    "source": [
     "We begin by using {py:func}`create_rectangle\n",
@@ -117,7 +117,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "ce69a131",
+   "id": "e6072ce8",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -130,7 +130,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "da219a8a",
+   "id": "935028ab",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -141,7 +141,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "890640fa",
+   "id": "b1ad8aba",
    "metadata": {},
    "source": [
     "The second argument to {py:class}`functionspace\n",
@@ -160,7 +160,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "7198605c",
+   "id": "4087e2b9",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -171,7 +171,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "b32228b7",
+   "id": "9f9122ef",
    "metadata": {},
    "source": [
     "We now find the degrees of freedom that are associated with the boundary\n",
@@ -182,7 +182,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "dc38cd5a",
+   "id": "d19ff0c0",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -191,7 +191,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "bbd94d85",
+   "id": "98f3ef90",
    "metadata": {},
    "source": [
     "and use {py:func}`dirichletbc <dolfinx.fem.dirichletbc>` to define the\n",
@@ -204,7 +204,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "0ea009b4",
+   "id": "b8524613",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -215,7 +215,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "21253427",
+   "id": "750406e8",
    "metadata": {},
    "source": [
     "Next, we express the variational problem using UFL."
@@ -224,7 +224,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "91b1b49e",
+   "id": "3027bdd6",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -239,7 +239,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "e3964ef8",
+   "id": "3c8efc1e",
    "metadata": {},
    "source": [
     "For the matrix-free solvers we also define a second linear form `M` as\n",
@@ -255,7 +255,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "41b7d091",
+   "id": "fff588d7",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -266,7 +266,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "94339e25",
+   "id": "5bb5710f",
    "metadata": {},
    "source": [
     "### Matrix-free conjugate gradient solver\n",
@@ -280,7 +280,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "8556a488",
+   "id": "b5700be2",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -295,7 +295,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "a557df13",
+   "id": "065dec84",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -306,7 +306,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "d264e727",
+   "id": "54c1195d",
    "metadata": {
     "lines_to_next_cell": 2
    },
@@ -318,7 +318,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "268bced0",
+   "id": "d46a58c7",
    "metadata": {
     "lines_to_next_cell": 2
    },
@@ -341,7 +341,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "78bde8ce",
+   "id": "d8491d6f",
    "metadata": {
     "lines_to_next_cell": 2
    },
@@ -357,7 +357,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "0a0401e7",
+   "id": "60cf8541",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -403,7 +403,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "7b71c3c1",
+   "id": "7a1df268",
    "metadata": {},
    "source": [
     "This matrix-free solver is now used to compute the finite element solution.\n",
@@ -414,7 +414,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "2131b21e",
+   "id": "5f10a4bb",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -426,7 +426,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "76e538fd",
+   "id": "5ae9d68a",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -437,7 +437,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "57004076",
+   "id": "15f7ad12",
    "metadata": {},
    "outputs": [],
    "source": [
@@ -449,7 +449,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "d0a71cf3",
+   "id": "63f253ac",
    "metadata": {},
    "outputs": [],
    "source": [

diff --git a/dolfinx/main/python/_downloads/9ed4657d08dda04de30e6463e2f58d75/demo_mixed-poisson.ipynb b/dolfinx/main/python/_downloads/9ed4657d08dda04de30e6463e2f58d75/demo_mixed-poisson.ipynb
@@ -2,15 +2,15 @@
  "cells": [
   {
    "cell_type": "markdown",
-   "id": "aa906794",
+   "id": "3c82d238",
    "metadata": {},
    "source": [
     "# Mixed formulation for the Poisson equation"
    ]
   },
   {
    "cell_type": "markdown",
-   "id": "121bf794",
+   "id": "0fefe3c6",
    "metadata": {},
    "source": [
     "This demo illustrates how to solve Poisson equation using a mixed\n",
@@ -22,7 +22,7 @@
   },
   {
    "cell_type": "markdown",
-   "id": "bf0cf900",
+   "id": "5d022230",
    "metadata": {},
    "source": [
     "```{admonition} Download sources\n",
@@ -103,7 +103,7 @@
   {
    "cell_type": "code",
    "execution_count": null,
-   "id": "46f0e3b9",
+   "id": "f5ea0714",
    "metadata": {},
    "outputs": [],
    "source": [