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It works when kwargs contains some keyword arguments. Normally, function definitions with 0 keyword arguments are handled by the parser and converted to a keyword-less function definition, so it's not usually a problem:
This code fails on Julia 0.4, with a
syntax errror: malformed expression
.It works when kwargs contains some keyword arguments. Normally, function definitions with 0 keyword arguments are handled by the parser and converted to a keyword-less function definition, so it's not usually a problem:
but it's a (minor) issue when writing function definition macros.
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