Convert a Rust struct to a Python tuple

[JackAshwell11]

If I have this Rust struct:

#[derive(FromPyObject, PartialEq, Eq, Hash, Clone, Copy, Debug)]
pub struct Point {
    pub x: isize,
    pub y: isize,
}

How can it be converted into a Python tuple upon returning it from a function?

[davidhewitt]

At the moment we don't have a #[derive] for the into-Python direction (we might have one eventually), however at the moment this is easy enough by just returning a Rust tuple of the fields:

#[pyfunction]
fn point_to_tuple(point: Point) -> (isize, isize) {
    (point.x, point.y)
}

[JackAshwell11]

I have this so far, is it okay?

#[derive(FromPyObject, PartialEq, Eq, Hash, Clone, Copy, Debug)]
pub struct Point {
    pub x: i32,
    pub y: i32,
}

impl IntoPy<PyObject> for Point {
    fn into_py(self, py: Python<'_>) -> PyObject {
        PyObject::from(PyTuple::new(py, [self.x, self.y]))
    }
}

[davidhewitt]

Yes, you can also just do it like this:

#[derive(FromPyObject, PartialEq, Eq, Hash, Clone, Copy, Debug)]
pub struct Point {
    pub x: i32,
    pub y: i32,
}

impl IntoPy<PyObject> for Point {
    fn into_py(self, py: Python<'_>) -> PyObject {
        (self.x, self.y).into_py(py)
    }
}

[JackAshwell11]

That works great. Thanks.