python-quadratic-roots

Python Program to Solve Quadratic Equation To understand this example, you should have the knowledge of the following Python programming topics:

Python Data Types Python Basic Input and Output Python Operators The standard form of a quadratic equation is:

ax2 + bx + c = 0, where a, b and c are real numbers and a ≠ 0 The solutions of this quadratic equation is given by:

(-b ± (b ** 2 - 4 _ a _ c) ** 0.5) / (2 * a) Source Code

Solve the quadratic equation ax**2 + bx + c = 0

import complex math module

import cmath

a = 1 b = 5 c = 6

calculate the discriminant

d = (b*2) - (4a*c)

find two solutions

sol1 = (-b-cmath.sqrt(d))/(2a) sol2 = (-b+cmath.sqrt(d))/(2a)

print('The solution are {0} and {1}'.format(sol1,sol2)) Run Code Output

Enter a: 1 Enter b: 5 Enter c: 6 The solutions are (-3+0j) and (-2+0j) We have imported the cmath module to perform complex square root. First, we calculate the discriminant and then find the two solutions of the quadratic equation.

You can change the value of a, b and c in the above program and test this program.