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Block transparent colors without allowTransparency #2

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merged 1 commit into from
Mar 30, 2018

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bgw
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@bgw bgw commented Mar 29, 2018

Fixes xtermjs#1357.

cc @Tyriar

I could probably add a test with some more mocking, but I'd rather try to get the node-canvas stuff in #1 landed.

return {
css,
rgba: data[0] << 24 | data[1] << 16 | data[2] << 8 | data[3]
rgba: (data[0] << 24 | data[1] << 16 | data[2] << 8 | data[3]) >>> 0
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What does this do?

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Coerces it to an unsigned int. There's some comments about this earlier in the file.

It's not really necessary (the bits are the same), but tends to make the resulting value more legible.

this.colors.cursor = this._parseColor(theme.cursor, DEFAULT_CURSOR);
this.colors.cursorAccent = this._parseColor(theme.cursorAccent, DEFAULT_CURSOR_ACCENT);
this.colors.selection = this._parseColor(theme.selection, DEFAULT_SELECTION);
this.colors.cursor = this._parseColor(theme.cursor, DEFAULT_CURSOR, true);
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Shouldn't the cursor use this.allowTransparency?

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The cursor is drawn on a separate transparent render layer, so it should be possible to use a transparent cursor without allowTransparency, similar to how you can do a transparent selection.

@Tyriar
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Tyriar commented Mar 29, 2018

LGTM

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2 participants