Preserve module name when subscripting a type from the 'typing' module

When no module name is passed, it defaults to the empty string,
which leads to an incorrect qname on the inferrence result.

astroid/brain/brain_typing.py

@@ -82,7 +82,10 @@ def infer_typing_attr(node, context=None):
     if not value.qname().startswith("typing."):
         raise UseInferenceDefault
 
-    node = extract_node(TYPING_TYPE_TEMPLATE.format(value.qname().split(".")[-1]))
+    node = extract_node(
+        TYPING_TYPE_TEMPLATE.format(value.qname().split(".")[-1]),
+        "typing"
+    )
     return node.infer(context=context)
 
 

tests/unittest_brain.py

@@ -1080,6 +1080,17 @@ def test_typing_namedtuple_dont_crash_on_no_fields(self):
         inferred = next(node.infer())
         self.assertIsInstance(inferred, astroid.Instance)
 
+    def test_generic_subscript(self):
+        node = builder.extract_node(
+            """
+        from typing import Generic, TypeVar
+        T = TypeVar('T')
+        Generic[T]  #@
+        """
+        )
+        inferred = next(node.infer())
+        self.assertEqual(inferred.qname(), "typing.Generic")
+
 
 class ReBrainTest(unittest.TestCase):
     def test_regex_flags(self):