wrong where-statement output when comparing the value of columns

[Fluit]

Information

• Version of Medoo: 2.1.2
• Type of Database (MySQL, MSSQL, SQLite...): MySQL
• System (Liunx\Windows\Mac): Windows

Describe the Problem
According to the documentation Columns Relationship I use ["fld1[=]fld2"] as a condition for comparing the values of the 2 columns. Instead of WHERE fld1 = fld2 i get WHERE fld1 = "fld1[=]fld2"

Detail Code
$this->Db->select('tbl1', ["[><]tbl2" => ['id' => 'tbl1_id']], ['fld1', 'fld2', ....], ["fld1[=]fld2"]) results in sql-string SELECT * tbl1 INNER JOIN tbl2 ON tbl1.id = tbl2.tb1_id WHERE fld1 = "fld1[=]fld2"
FYI: fld1 & fld2 are unique fieldnames in tbl2!
Even changing the where-array in ['tbl2.fld1[=]tbl2.fld2"] makes no difference.

It looks like the second part of the condition is not quoted correctly.

Expected output
is should be ... SELECT * tbl1 INNER JOIN tbl2 ON tbl1.id = tbl2.tb1_id WHERE tbl2.fld1 = tbl2.fld2"

[Fluit]

A workaround is using Medoo;;raw statement: ['fld1' => \Medoo\Medoo::raw('<tbl2.fld2>')]

[catfan]

That's a bug. Fixed it on 6f9a6c6.

[Fluit]

Tested and approved!

thanks.