Task 1 completed #5 (#75)

* Create Question.md

* Add solution of Task 1 cpp problem

Task 1/2D Array - Alternating rectangles of O and X/Question.md

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+# 2D Array - Alternating rectangles of O and X
+Write a code which inputs two numbers m and n and creates a matrix of size m x n (m rows and n columns) in which every elements is either X or 0. The Xs and 0s must be filled alternatively, the matrix should have outermost rectangle of Xs, then a rectangle of 0s, then a rectangle of Xs, and so on.. 
+
+### Input Format
+You need to tell that how many rows and columns your matrix need to have and these values should be separated by space.
+### Constraints
+1 <= n,m <= 1000
+### Output Format
+Print the resultant matrix to the stdout.
+### [Link of the question](https://www.techgig.com/practice/question/2d-array-alternating-rectangles-of-o-and-x/MXExbVBCMm83Y0ROcG42RXg2V1hhMy83Skwxdjh0ZWZjZEpqOE1uWEs1QzZINW9DR0dPYXpXR1pvVzJ5N3BpSA==/1)
+## Sample TestCase 1
+#### input
+```
+6 7
+```
+#### output
+```
+X X X X X X X
+X 0 0 0 0 0 X
+X 0 X X X 0 X
+X 0 X X X 0 X
+X 0 0 0 0 0 X
+X X X X X X X
+```
+**Time Limit(X)** : 1.00 sec(s) for each input.
+
+**Memory Limit** : 512 MB

Task 1/2D Array - Alternating rectangles of O and X/Solution.cpp

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+#include<iostream>
+using namespace std;
+int main()
+{
+  int m, n;
+  cin>>m>>n;
+  if(n>=1 && m <= 1000 && m>=1 && n<=1000)
+  {
+    int i, j, k=0, p=0, checkr=0, checkc=0;
+    char mat[m][n];
+
+        for (i=1; i<=m; i++)
+        {
+            p=0;
+            checkc=0;
+            for(j=1; j<=n; j++)
+            {
+                if((checkr==0 && j>=k+1 && j<=n-k) || (checkc==0 && i>=p+1 && i<m-p))
+                {
+                    mat[i][j]='X';
+                    cout<<mat[i][j];
+                }
+                else
+                {
+                    mat[i][j]='0';
+                    cout<<mat[i][j];
+                }
+                if(n%2==0)
+                {
+                    if(j<n/2)
+                        p++;
+                    else if(j==n/2)
+                        p=p;
+                    else
+                        p--;
+                }
+                else if(n%2==1)
+                {
+                    if(j<(n+1)/2)
+                        p++;
+                    else
+                        p--;
+                }
+                if(n%2==0 && j==n/2)
+                    checkc=checkc;
+                else
+                    checkc=1-checkc;
+                if(j<=n-1)
+                    cout<<" ";
+            }
+            if(m%2==0)
+            {
+                if(i<m/2)
+                    k++;
+                else if(i==m/2)
+                    k=k;
+                else
+                    k--;
+            }
+            else if(m%2==1)
+            {
+                if(i<(m+1)/2 )
+                    k++;
+                else
+                    k--;
+            }
+
+            if(m%2==0 && i==m/2)
+                checkr=checkr;
+            else
+                checkr=1-checkr;
+            if(i<=m-1)
+                cout<<"\n";
+        }
+
+    return 0;
+  }
+}