Making coerce to be a type argument

[RobinTail]

Fixes #1760

This PR makes the schema types, that support coerce feature, to have the correct type of the input schema if this feature is enabled.

Thus, z.coerce.number() will have the type compatible to ZodType<number, ZodNumberDef, any>.
Third type argument stands for input type, which in case of coerce accepts anything.

Therefore, taking z.input<> on such schema will return any.

The behavior of schemas and methods without coerce feature, of having that feature disabled, remains the same.

Thanks to the default values of the new type argument, this change is backward compatible.

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[RobinTail]

The test with Deno fails due to some issue within the master branch

[RobinTail]

Should be fixed after merging #1794

[RobinTail]

@JacobWeisenburger || @colinhacks , please review

[JacobWeisenburger]

Unfortunately, I don't think I have enough experience to approve this. Perhaps @colinhacks or @scotttrinh would be able to help.

[RobinTail]

Ok. I updated the description for the clarity.

[RobinTail]

@colinhacks || @scotttrinh , please review

[RobinTail]

[aleclarson]

Why not create a new ZodCoercedString type (plus the others) instead of complicating the existing types?

Also, I don't think any is the correct type to return from z.input. Although, it's probably fine until TypeScript gets negated types?

[colinhacks]

Discussed this under the original issue: #1760 (comment)

[stale]

This issue has been automatically marked as stale because it has not had recent activity. It will be closed if no further activity occurs. Thank you for your contributions.