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Update flatten definition #2713
Update flatten definition #2713
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... which falls back to case-analysis on the bound of
X
, which means we use the bound, even on a promoted type variable, if it's promoted to a non-future-value-having type.I'd say
\DefEquals{\flatten{T}}{\code{X}}
to be consistent with what we have now.Example:
<X extends FutureOr<Object?>>
andX o = ...;
o
toX & Object
byo is Object
.await o
.X&Object
has no future value type, so we fall back on flatten(X
)X
has future typeObject?
.await o
, witho
of typeX & Object
, has typeObject?
.It's not unsound, because a result type of
Object?
never is, but I'm not absolutely sure it's what we want.(Not entirely sure it isn't either. But I want to be sure either way.)
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Yes flatten(
X & Object
) is flatten(X
), becauseObject
does not have a future type.But
X
has future typeFutureOr<Object?>
so flatten(X
) isObject?
. Soawait o
will awaito
and get theObject?
, statically typed asObject?
, which is sound.I guess you're saying that if the developer tests explicitly for
o is Object
then we're supposed to forget that we know that anything-X
is aFuture<Object?>
as well.It is not obvious to me that this would be the natural behavior. I tend to think it's OK to find the future type in the type variable in the case where the other operand of the intersection type doesn't have any.