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12.2.1 Expression classifications|General #192
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I could be missing something here, but I think the standard is right. The is/as/typeof operators are defined using "type" directly rather than using "expression", so we don't need "an expression which is classified as a type" to be valid for their operands. Proposal: stick with v5, but please validate carefully! |
We should add that it can be the operand of a |
Resolution:
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2020-06-25 Teleconference: The v5 spec is correct; no change needed; review for v6. |
For |
In the list accompanying “An expression is classified as one of the following:”, v5std has
while v6spec has
What to do?
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