XML support for Django REST Framework
Full documentation for the project is available at http://jpadilla.github.io/django-rest-framework-xml.
XML support extracted as a third party package directly from the official Django REST Framework implementation. It requires the defusedxml package only because it safeguards against some security issues that were discovered.
Note: XML output provided is an ad-hoc format that isn't formally described. If you have specific XML requirements you'll need to write your own XML parsers/renderers in order to fully control the representation.
- Python 3.5+
- Django 2.2+
- Django REST Framework 3.11+
Install using pip
...
$ pip install djangorestframework-xml
REST_FRAMEWORK = {
'DEFAULT_PARSER_CLASSES': (
'rest_framework_xml.parsers.XMLParser',
),
'DEFAULT_RENDERER_CLASSES': (
'rest_framework_xml.renderers.XMLRenderer',
),
}
You can also set the renderer and parser used for an individual view, or viewset, using the APIView class based views.
from rest_framework import routers, serializers, viewsets
from rest_framework_xml.parsers import XMLParser
from rest_framework_xml.renderers import XMLRenderer
class UserSerializer(serializers.HyperlinkedModelSerializer):
class Meta:
model = User
fields = ('url', 'username', 'email', 'is_staff')
class UserViewSet(viewsets.ModelViewSet):
queryset = User.objects.all()
serializer_class = UserSerializer
parser_classes = (XMLParser,)
renderer_classes = (XMLRenderer,)
<?xml version="1.0" encoding="utf-8"?>
<root>
<list-item>
<url>http://127.0.0.1:8000/users/1/.xml</url>
<username>jpadilla</username>
<email>jpadilla@example.com</email>
<is_staff>True</is_staff>
</list-item>
</root>
Full documentation for the project is available at http://jpadilla.github.io/django-rest-framework-xml.
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