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Vidar Holen edited this page Nov 3, 2022 · 1 revision

In POSIX sh, |& in place of 2>&1 | is undefined.

Problematic code:

#!/bin/sh
make |& tee ~/log

Correct code:

Either switch to bash:

#!/bin/sh
make 2>&1 | tee ~/log

Rationale:

Your script uses a shell feature not supported by the shebang. Either rewrite the script to be portable, or change the shebang to explicitly require a shell like Bash.

In this case, the non-portable shorthand |& to pipe both stdout and stderr can be easily replaced with its written out form 2>&1 | as shown.

Exceptions:

None

Related resources:

  • Help by adding links to BashFAQ, StackOverflow, man pages, POSIX, etc!

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