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NPeersForCpl and collapse empty buckets #77
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Original file line number | Diff line number | Diff line change | ||||||||
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@@ -85,6 +85,58 @@ func (rt *RoutingTable) Close() error { | |||||||||
return nil | ||||||||||
} | ||||||||||
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// NPeersForCPL returns the number of peers we have for a given Cpl | ||||||||||
func (rt *RoutingTable) NPeersForCpl(cpl uint) int { | ||||||||||
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rt.tabLock.RLock() | ||||||||||
defer rt.tabLock.RUnlock() | ||||||||||
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// it's in the last bucket | ||||||||||
if int(cpl) >= len(rt.buckets)-1 { | ||||||||||
count := 0 | ||||||||||
b := rt.buckets[len(rt.buckets)-1] | ||||||||||
for _, p := range b.peerIds() { | ||||||||||
if CommonPrefixLen(rt.local, ConvertPeerID(p)) == int(cpl) { | ||||||||||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Should be using There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. This is done. |
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count++ | ||||||||||
} | ||||||||||
} | ||||||||||
return count | ||||||||||
} else { | ||||||||||
return rt.buckets[cpl].len() | ||||||||||
} | ||||||||||
} | ||||||||||
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// GetPeersForCpl returns the peers in the Routing Table with this cpl. | ||||||||||
func (rt *RoutingTable) GetPeersForCpl(cpl uint) []peer.ID { | ||||||||||
rt.tabLock.RLock() | ||||||||||
defer rt.tabLock.RUnlock() | ||||||||||
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var peers []peer.ID | ||||||||||
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// it's in the last bucket | ||||||||||
if int(cpl) >= len(rt.buckets)-1 { | ||||||||||
b := rt.buckets[len(rt.buckets)-1] | ||||||||||
for _, p := range b.peerIds() { | ||||||||||
if CommonPrefixLen(rt.local, ConvertPeerID(p)) == int(cpl) { | ||||||||||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Should be using There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. We've removed this function. |
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peers = append(peers, p) | ||||||||||
} | ||||||||||
} | ||||||||||
} else { | ||||||||||
for _, p := range rt.buckets[cpl].peerIds() { | ||||||||||
peers = append(peers, p) | ||||||||||
} | ||||||||||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more.
Suggested change
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. We don't need this function anymore. |
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} | ||||||||||
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return peers | ||||||||||
} | ||||||||||
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// IsBucketFull returns true if the Logical bucket for a given Cpl is full | ||||||||||
func (rt *RoutingTable) IsBucketFull(cpl uint) bool { | ||||||||||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Is this function used for anything, or just here for convenience/to be more efficient then There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. We've removed this function now. |
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rt.tabLock.RLock() | ||||||||||
defer rt.tabLock.RUnlock() | ||||||||||
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return rt.NPeersForCpl(cpl) == rt.bucketsize | ||||||||||
} | ||||||||||
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// TryAddPeer tries to add a peer to the Routing table. If the peer ALREADY exists in the Routing Table, this call is a no-op. | ||||||||||
// If the peer is a queryPeer i.e. we queried it or it queried us, we set the LastSuccessfulOutboundQuery to the current time. | ||||||||||
// If the peer is just a peer that we connect to/it connected to us without any DHT query, we consider it as having | ||||||||||
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@@ -117,6 +169,11 @@ func (rt *RoutingTable) addPeer(p peer.ID, queryPeer bool) (bool, error) { | |||||||||
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// peer already exists in the Routing Table. | ||||||||||
if peer := bucket.getPeer(p); peer != nil { | ||||||||||
// if we're querying the peer first time after adding it, let's give it a | ||||||||||
// usefulness bump. This will ONLY happen once. | ||||||||||
if peer.LastUsefulAt.IsZero() && queryPeer { | ||||||||||
peer.LastUsefulAt = lastUsefulAt | ||||||||||
} | ||||||||||
Comment on lines
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Is this fix related to the rest of the PR, or just a "while I'm already here" kind of thing? There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Hey, This change is not related to the rest of the PR. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. No problem, while you're here and changing this do you mind add more information to the |
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return false, nil | ||||||||||
} | ||||||||||
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@@ -230,7 +287,21 @@ func (rt *RoutingTable) removePeer(p peer.ID) { | |||||||||
if bucket.remove(p) { | ||||||||||
// peer removed callback | ||||||||||
rt.PeerRemoved(p) | ||||||||||
return | ||||||||||
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// remove this bucket if it was the last bucket and it's now empty | ||||||||||
// provided it isn't the ONLY bucket we have. | ||||||||||
if len(rt.buckets) > 1 && bucketID == len(rt.buckets)-1 && len(bucket.peers()) == 0 { | ||||||||||
rt.buckets[bucketID] = nil | ||||||||||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Might be just blanking here, but why are we doing this? Does it help the garbage collector out in some way? There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. It helps the GC garbage collect the struct pointed to by the slice element as I understand from here: https://github.com/golang/go/wiki/SliceTricks (Look at the section on |
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rt.buckets = rt.buckets[:bucketID] | ||||||||||
return | ||||||||||
} | ||||||||||
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// if the second last bucket just became empty, remove and replace it with the last bucket. | ||||||||||
if bucketID == len(rt.buckets)-2 && len(bucket.peers()) == 0 { | ||||||||||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I don't think this is good enough, as is shown in my test comment. What happens if we have buckets 1,2,3,4 and remove the peers from buckets 2 then 3 then 4? Here we'll collapse bucket 4 into bucket 3 and bucket 3 into bucket 2, leaving us with two total buckets instead of just one. Perhaps doing this in a for loop would be better so we can close all buckets at the end that are empty. There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. I agree and this has been fixed. |
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rt.buckets[bucketID] = rt.buckets[bucketID+1] | ||||||||||
rt.buckets[bucketID+1] = nil | ||||||||||
rt.buckets = rt.buckets[:bucketID+1] | ||||||||||
} | ||||||||||
} | ||||||||||
} | ||||||||||
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can you get away without this function, and just call
len(GetPeersForCpl)
instead?There was a problem hiding this comment.
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Have removed
GetPeersForCpl
as we don't need it anymore.There was a problem hiding this comment.
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We've removed
GetPeersForCpl
as we don't need it anymore.There was a problem hiding this comment.
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I guess this is a tiny bit more efficient then just
len(GetPeersForCpl)
and we can always addGetPeersForCpl
back in if we need it. Your call 😄