isDisjoint

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Subhajit Sahu edited this page Dec 2, 2022 · 17 revisions

Check if sets have no value in common.

Similar: union, intersection, difference, symmetricDifference, isDisjoint.

function isDisjoint(x, y)
// x: a set
// y: another set

const set = require('extra-set');

var x = new Set([1, 2, 3]);
var y = new Set([3, 4]);
set.isDisjoint(x, y);
// → false

var y = new Set([4]);
set.isDisjoint(x, y);
// → true

References