Add this suggestion to a batch that can be applied as a single commit.
This suggestion is invalid because no changes were made to the code.
Suggestions cannot be applied while the pull request is closed.
Suggestions cannot be applied while viewing a subset of changes.
Only one suggestion per line can be applied in a batch.
Add this suggestion to a batch that can be applied as a single commit.
Applying suggestions on deleted lines is not supported.
You must change the existing code in this line in order to create a valid suggestion.
Outdated suggestions cannot be applied.
This suggestion has been applied or marked resolved.
Suggestions cannot be applied from pending reviews.
Suggestions cannot be applied on multi-line comments.
Suggestions cannot be applied while the pull request is queued to merge.
Suggestion cannot be applied right now. Please check back later.
There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
Does using
breakOnSigint
option start a new event loop though? Either I am wrong or the language is somewhat confusing here.There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
Yeah,
breakOnSigint
doesn’t start its own loop, only an extra thread. It’s definitely just an implementation detail, but if you have suggestions for better wording, I’ll take them. :)There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
I'd say something like "Using the
timeout
option will result in creating a new event loop and utilizing thebreakOnSigint
option will cause a helper thread to be started", but, well, I agree that it is an implementation detail and your version is more concise, so I'm fine with it either way.There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
@aqrln The
timeout
option will create both a thread and a new event loop. ;) (I would actually assume spinning up the thread is much more costly – basically, what I’m trying to say is that both will allocate and consume new resources.)There was a problem hiding this comment.
Choose a reason for hiding this comment
The reason will be displayed to describe this comment to others. Learn more.
Maybe remove
non-zero