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Irrefutable if let
on a single-variant enum only produces () value
#61788
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You can match irrefutably without fn stuff(x: Enum) -> i32 {
let Enum::Variant(value) = x;
value
} though maybe we should give this special diagnostics. |
I think this is too niche to deserve a special diagnostics (and I don't think we should substantially work on diagnostics for
if let PAT = EXPR BLOCK_IF [else BLOCK_ELSE] becomes: match EXPR {
PAT => BLOCK_IF,
_ => [ {} | BLOCK_ELSE ],
} so what you really wrote is: match x {
Enum::Variant(value) => value,
_ => {},
} The block |
I didn't know (With that knowledge in mind) I agree that it's only a diagnostics issue and no language change is needed here. |
I think the appropriate thing to do here would be to lint on |
But we do only after typechecking, and we don't if there are any errors before then. Quite a few lints have similar issues related to not happening early enough. |
@estebank How do you know that the pattern is irrefutable before match checking in HAIR? |
You can't, but you can write the lint in such a way that it triggers regardless. We're getting to typechecking, we should be able to detect irrefutability by then. It just can't use the standard linting machinery (like a few other lints already do to avoid being silenced by accident). |
When encountering an `if let` tail expression without an `else` arm for an enum with a single variant, suggest writing an irrefutable `let` binding instead. ``` error[E0317]: `if` may be missing an `else` clause --> $DIR/irrefutable-if-let-without-else.rs:8:5 | LL | fn foo(x: Enum) -> i32 { | --- expected `i32` because of this return type LL | / if let Enum::Variant(value) = x { LL | | value LL | | } | |_____^ expected `i32`, found `()` | = note: `if` expressions without `else` evaluate to `()` = help: consider adding an `else` block that evaluates to the expected type help: consider using an irrefutable `let` binding instead | LL ~ let Enum::Variant(value) = x; LL ~ value | ``` Fix rust-lang#61788.
When encountering an `if let` tail expression without an `else` arm for an enum with a single variant, suggest writing an irrefutable `let` binding instead. ``` error[E0317]: `if` may be missing an `else` clause --> $DIR/irrefutable-if-let-without-else.rs:8:5 | LL | fn foo(x: Enum) -> i32 { | --- expected `i32` because of this return type LL | / if let Enum::Variant(value) = x { LL | | value LL | | } | |_____^ expected `i32`, found `()` | = note: `if` expressions without `else` evaluate to `()` = help: consider adding an `else` block that evaluates to the expected type help: consider using an irrefutable `let` binding instead | LL ~ let Enum::Variant(value) = x; LL ~ value | ``` Fix rust-lang#61788.
Suggest turning `if let` into irrefutable `let` if appropriate When encountering an `if let` tail expression without an `else` arm for an enum with a single variant, suggest writing an irrefutable `let` binding instead. ``` error[E0317]: `if` may be missing an `else` clause --> $DIR/irrefutable-if-let-without-else.rs:8:5 | LL | fn foo(x: Enum) -> i32 { | --- expected `i32` because of this return type LL | / if let Enum::Variant(value) = x { LL | | value LL | | } | |_____^ expected `i32`, found `()` | = note: `if` expressions without `else` evaluate to `()` = help: consider adding an `else` block that evaluates to the expected type help: consider using an irrefutable `let` binding instead | LL ~ let Enum::Variant(value) = x; LL ~ value | ``` Fix rust-lang#61788.
Suggest turning `if let` into irrefutable `let` if appropriate When encountering an `if let` tail expression without an `else` arm for an enum with a single variant, suggest writing an irrefutable `let` binding instead. ``` error[E0317]: `if` may be missing an `else` clause --> $DIR/irrefutable-if-let-without-else.rs:8:5 | LL | fn foo(x: Enum) -> i32 { | --- expected `i32` because of this return type LL | / if let Enum::Variant(value) = x { LL | | value LL | | } | |_____^ expected `i32`, found `()` | = note: `if` expressions without `else` evaluate to `()` = help: consider adding an `else` block that evaluates to the expected type help: consider using an irrefutable `let` binding instead | LL ~ let Enum::Variant(value) = x; LL ~ value | ``` Fix rust-lang#61788.
Rollup merge of rust-lang#120479 - estebank:issue-61788, r=wesleywiser Suggest turning `if let` into irrefutable `let` if appropriate When encountering an `if let` tail expression without an `else` arm for an enum with a single variant, suggest writing an irrefutable `let` binding instead. ``` error[E0317]: `if` may be missing an `else` clause --> $DIR/irrefutable-if-let-without-else.rs:8:5 | LL | fn foo(x: Enum) -> i32 { | --- expected `i32` because of this return type LL | / if let Enum::Variant(value) = x { LL | | value LL | | } | |_____^ expected `i32`, found `()` | = note: `if` expressions without `else` evaluate to `()` = help: consider adding an `else` block that evaluates to the expected type help: consider using an irrefutable `let` binding instead | LL ~ let Enum::Variant(value) = x; LL ~ value | ``` Fix rust-lang#61788.
The following code (playground)
gives the following error:
which is weird, since the
else
clause would never be visited even if it was present.The equivalent one-arm match
compiles just fine (expectedly).
Adding an
else { unreachable!() }
branch to theif let
is, of course, possible, but unelegant, and really shouldn't be needed, as it can be inferred at compile time.The text was updated successfully, but these errors were encountered: