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It's surprising to me that there was an explicit big-endian mention here before, but now it's using native-endian. Obviously the doctest is passing on the little-endian test machine, but are we sure this is correct? Is it possible that, for clarity, it should be written differently? Maybe
(It's still fully efficient, as LLVM knows that
bswap(bswap(x)) == x
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Yes, because
s_addr
is always in big endian order andoctets
methods returns data in big endian order too. So we just wanna return bytes as they are and yes, in that case isto_ne_bytes
little lie. But I am not sure if your proposed solution will more clarify that, maybe write some comment?There was a problem hiding this comment.
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If it's right that's the important thing :)
(A comment with your first sentence there might be nice, though. Up to you.)