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prose: fix typos
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TOTBWF committed Jan 10, 2025
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10 changes: 5 additions & 5 deletions src/Cat/Displayed/TwoSided.lagda.md
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Expand Up @@ -46,12 +46,12 @@ A displayed category $\cE \liesover \cA \times \cB$ is a **two-sided fibration**
when it satisfies the following 3 conditions:

1. For every $u : \cA(A_1, A_2)$, $B : \cB$ and $Y : \cE_{A_2, B}$, there
exists a [[cartesian lift]] $u^{*} : \cE_{u, \id}(u^{*}(Y), Y)$.
exists a [[cartesian lift]] $\pi_{u, Y} : \cE_{u, \id}(u^{*}(Y), Y)$.

2. For every $A : \cA, v : \cB(B_1, B_2)$ and $X : \cE_{A, B_1}$, there
exists a [[cocartesian lift]] $v_{!} : \cE_{\id, v}(X, v_{!}(X))$.
exists a [[cocartesian lift]] $\iota_{v, X} : \cE_{\id, v}(X, v_{!}(X))$.

3. For every a diagram of the form below with $f$ cocartesian and $g$ cartesian,
3. For every diagram of the form below with $f$ cocartesian and $g$ cartesian,
$h$ is cartesian if and only if $k$ is cocartesian.

~~~{.quiver}
Expand Down Expand Up @@ -119,7 +119,7 @@ This definition is rather opaque, so let's break it down. The first two
conditions ensure that we have 2 functorial actions on each of the [[fibre categories]]
$E_{a, b}$: the first acts contravariantly in $\cA$, the second covariantly
in $\cB$. This is analogous to the actions $P(-, \id)$ and $P(\id, -)$ for
a profunctor $P : \cA \times \cB \to \Sets$. The final condition servers to
a profunctor $P : \cA \times \cB \to \Sets$. The final condition serves to
ensure that the [[base change]] and [[cobase change]] functors
$u^{*} : \cE_{A_2, B} \to \cE_{A_1, B}$ and $v_{!} : \cE_{A, B_1} \to \cE{A, B_2}$
$u^{*} : \cE_{A_2, B} \to \cE_{A_1, B}$ and $v_{!} : \cE_{A, B_1} \to \cE_{A, B_2}$
preserve cocartesian and cartesian morphisms, resp.
2 changes: 1 addition & 1 deletion src/Cat/Displayed/TwoSided/Discrete.lagda.md
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Expand Up @@ -291,7 +291,7 @@ $u : \cA(A_1, A_2), v : \cB(B_1, B_2)$.

All of our Hom sets are propositional, so constructing an inverse only
requires us to build a map $\cE_{u^{-1}, v^{-1}}(Y, X)$. Moreover, it
suffices to prove that $(u^{-1})^{*}(X) = v^{-1}_{!}(X)$, which follows
suffices to prove that $(u^{-1})^{*}(X) = (v^{-1})_{!}(X)$, which follows
from some tedious functoriality algebra.
```agda
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