Python Scripts for Generating Biochemistry, Genetics, and Molecular Biology Homework/Quiz problems
- Genetics Problems
- Biochemistry Problems
Created by gh-md-toc
What will the results of a blood test look like for a person with O- blood type?
- For the ABO blood group in humans, the iA and iB alleles are codominant and the i allele is recessive. If a female ♀ with type A blood marries a male ♂ with type O blood, which of the following blood types could their children possibly have? Check all that apply.
- A. Type O blood
- B. Type A blood
- C. Type B blood
- D. Type AB blood
- For the ABO blood group in humans, the iA and iB alleles are codominant and the i allele is recessive. A father ♂ who has blood type AB has a son ♂ who has blood type A, which of the following blood types could the mother ♀ possibly have? Check all that apply.
- A. Type O blood
- B. Type A blood
- C. Type B blood
- D. Type AB blood
- E. None of the above are possible
- Download list of 2 gene questions in blackboard upload format
- Download list of 3 gene questions in blackboard upload format
- A mother has a HLA genotype of A2,B5,C6 on one chromosome and A1,B1,C3 on the other. The father has a HLA genotype of A7,B9,C2 on one chromosome and A8,B3,C5 on the other. Which one of the following is a possible genotype for one of their offspring?
- A. A2,A8,B1,B9,C2,C3
- B. A1,A2,B1,B5,C3,C6
- C. A2,A7,B5,B9,C2,C6
- D. A7,A8,B3,B9,C2,C5
- E. A1,A7,B1,B3,C5,C6
- How many unique gametes could be produced through independent assortment by an individual with the genotype AA Bb cc dd Ee Ff Gg ?
- A. 22 = 4
- B. 23 = 8
- C. 24 = 16
- D. 25 = 32
- E. 26 = 64
- In a specific cross, F2 progeny exhibit a modified dihybrid ratio of 15:1 (instead of 9:3:3:1 ). What phenotypic ratio would be expected from a test-cross with an individual from the F1 progeny?
- A. 1:4
- B. 2:2 or 1:1
- C. 4:1
- D. 3:1
- E. 2:1
- F. 1:3
- An F1 heterozygote individual from dihybrid cross is used for a test-cross. The progeny from the test-cross exhibited a modified ratio of 3:1 (instead of 1:1:1:1). What phenotypic ratio would be expected in the F2 progeny if the dihybrid cross is continued?
- A. 13:3
- B. 12:4
- C. 11:5
- D. 10:6
- E. 9:7
1. The white-eyed phenotype is an X-linked recessive disorder in fruit flies. The red allele, +, is dominant to the white allele, w. The offspring of size 400 from the mating of a single female and a single male are shown in the table below:
phenotype | female ♀ | male ♂ |
---|---|---|
red-eyed (wildtype) | 0 | 0 |
white-eyed (mutant) | 185 | 215 |
What are the genotypes of the parents in this cross?
- A. homozygous wildtype female (++) and male of unknown genotype
- B. heterozygous female (+w) and wildtype male (+–)
- C. heterozygous female (+w) and mutant male (w–)
- D. homozygous mutant female (ww) and wildtype male (+–)
- E. homozygous mutant female (ww) and mutant male (w–)
Table of Chi-Squared (χ2) Critical Values | ||||||||
---|---|---|---|---|---|---|---|---|
Degrees of Freedom | Probability | |||||||
0.95 | 0.90 | 0.75 | 0.50 | 0.25 | 0.10 | 0.05 | 0.01 | |
1 | 0.00 | 0.02 | 0.10 | 0.45 | 1.32 | 2.71 | 3.84 | 6.63 |
2 | 0.10 | 0.21 | 0.58 | 1.39 | 2.77 | 4.61 | 5.99 | 9.21 |
3 | 0.35 | 0.58 | 1.21 | 2.37 | 4.11 | 6.25 | 7.81 | 11.34 |
4 | 0.71 | 1.06 | 1.92 | 3.36 | 5.39 | 7.78 | 9.49 | 13.28 |
1. The final result gives the chi-squared (χ2) test value of 3.58 with 3 degrees of freedom. Using the Table of χ2 Critical Values and a level of significance α=0.50, we get a critical value of 2.37. Since the chi-squared (χ2) test value of 3.58 is greater than the critical value of 2.37, the null hypothesis was rejected.
Phenotype | Expected | Observed | Calculation | Statistic |
---|---|---|---|---|
Yellow Round (Y–R–) | 90 | 94 | (94-90)2⁄ 90 | 0.178 |
Yellow Wrinkled (Y–rr) | 30 | 21 | (21-30)2⁄ 30 | 2.700 |
Green Round (yyR–) | 30 | 33 | (33-30)2⁄ 30 | 0.300 |
Green Wrinkled (yyrr) | 10 | 12 | (12-10)2⁄ 10 | 0.400 |
(sum) χ2 = | 3.578 |
Your lab partner has done a chi-squared (χ2) test for your lab data (above), for the F2 generation in a standard dihybid cross. They wanted to know if the results confirm the expected phenotype ratios, but as usual they did something wrong. Where did they do wrong?
- A. the expected progeny for the null hypothesis is incorrect
- B. the degrees of freedom is wrong
- C. the numbers in the calculation have to be squared
- D. the wrong numbers in the calculation were used for division
- E. the wrong rejection criteria was used
A women has nine (9) children, what is the probability that she has exactly five (5) boys and four (4) girls?
Protein Name | isoelectric point (pI) | molecular weight |
---|---|---|
Xylosidase (Xyl) | 5.0 | 100.0 |
1. The protein in the table (above) is placed in a buffer solution with a pH of 6.0.
What is the correct net charge on the Xyl protein at pH of 6.0?
- A. The protein will have a net negative (–) charge
- B. The protein will have a net positive (+) charge
- C. The protein will have a neutral (0) charge
2. A mixture of two proteins are to be separated by isoelectric focusing.
Protein Name | isoelectric point (pI) | molecular weight |
---|---|---|
β-Galactosidase (Gal) | 4.6 | 175.0 |
Fumerase (Fum) | 7.6 | 48.5 |
Both protein samples are placed into a gel with a constant pH of 9.0. The gel is then placed into an electric field.
In which direction will each protein in the table migrate at pH 9.0
- A. Both Gal and Fum will travel towards the positive (+) terminal
- B. Both Gal and Fum will travel towards the negative (–) terminal
- C. Gal will travel towards the positive (+) and Fum will travel towards the negative (–)
- D. Gal will travel towards the negative (–) and Fum will travel towards the positive (+)
Protein Name | Molecular Weight (kDa) | Migration Distance (cm) |
---|---|---|
Ribonuclease A (RibA) | 13.7 | 3.41 |
Serine Protease (Ser) | 22.0 | 3.03 |
Prostate-Specific Antigen (PSA) | 30.0 | 2.78 |
Aldolase (Aldo) | 47.5 | 2.41 |
Fibrinogen (Fib) | 63.5 | 2.18 |
Unknown | ? | 2.89 |
3. The standard and unknown proteins listed in the table were run using SDS–PAGE.
Estimate the molecular weight of the unknown protein.
- A. 17 kDa
- B. 26 kDa
- C. 41 kDa
- D. 54 kDa
4. In a long α-helix, amino acid number 7 would form a hydrogen bond with which two other amino acids?
- A. 1 and 13
- B. 4 and 10
- C. 5 and 9
- D. 2 and 12
- E. 3 and 11
5. Based on their molecular formula, which one of the following compounds is most likely hydrophobic
- A. erythrose, C4H8O4
- B. acetate, C2H3O2
- C. ethylene, CH2CH2
- D. urea, CO(NH2)2
6. Michaelis-Menten question. The following question refers to the table (below) of enzyme activity.
substrate concentration [S] | initial reaction velocity V0 |
---|---|
0.001 | 30.0 |
0.002 | 51.5 |
0.005 | 90.0 |
0.010 | 120.1 |
0.020 | 144.0 |
0.050 | 163.7 |
0.100 | 171.5 |
0.200 | 175.7 |
0.500 | 178.3 |
1.000 | 179.2 |
10.000 | 180.0 |
Using the table (above), calculate the value for the Michaelis-Menten constant, KM.
- A. KM = 0.001
- B. KM = 0.002
- C. KM = 0.005
- D. KM = 0.020
- E. KM = 0.050
7. Michaelis-Menten question. The following question refers to the table (below) of enzyme activity with and without an inhibitor.
substrate concentration, [S] | initial reaction velocity no inhibitor V0 (–inh) | initial reaction velocity with inhibitor V0 (+inh) |
---|---|---|
0.0001 | 9.6 | 8.6 |
0.0002 | 18.2 | 16.4 |
0.0005 | 40.0 | 36.0 |
0.0010 | 66.7 | 60.0 |
0.0020 | 100.0 | 90.0 |
0.0050 | 142.9 | 128.6 |
0.0100 | 166.7 | 150.0 |
0.0200 | 181.9 | 163.7 |
0.0500 | 192.4 | 173.1 |
0.1000 | 196.1 | 176.5 |
1.0000 | 199.7 | 179.7 |
10.0000 | 200.0 | 180.0 |
Using the table (above), determine the type of inhibition.
- A. anticompetitive
- B. competitive
- C. noncompetitive
- D. ultracompetitive
- E. uncompetitive
1. Given the following peptide sequence, NH3+—Gln—Ala—Ala—Tyr—Ser—Asn—Glu—Glu—Gln—Gln—COO–, at which peptide bond location will chymotrypsin most likely cleave first?
- A. Ala—Tyr
- B. Tyr—Ser
- C. Glu—Gln
- D. Gln—Ala
- E. Ala—Ala
Above is a Fischer projection of the monosaccharide D-tagatose. Which one of the following Fischer projections is of the monosaccharide L-tagatose?