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Switch to uint8_t, some optimizations #979

Merged
merged 8 commits into from
Oct 20, 2024
Merged

Switch to uint8_t, some optimizations #979

merged 8 commits into from
Oct 20, 2024

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davepl
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@davepl davepl commented Oct 19, 2024

Description

Replace this text with your description.

Contributing requirements

  • I read the contribution guidelines in CONTRIBUTING.md.
  • I placed my solution in the correct solution folder.
  • I added a README.md with the right badge(s).
  • I added a Dockerfile that builds and runs my solution.
  • I selected drag-race as the target branch.
  • All code herein is licensed compatible with BSD-3.

davepl and others added 5 commits October 18, 2024 13:38
* Use latest Julia version to represent current performance (#972)

* Use latest Julia version to represent current performance

* Use latest stable 1.X version

* Add timeout to benchmark solution runs (#977)

* Added formatting and removed deprecated attributes syntax (#982)

Co-authored-by: Tudor Marghidanu <tudor@f2pool.io>

---------

Co-authored-by: Christian Guinard <28689358+christiangnrd@users.noreply.github.com>
Co-authored-by: Tudor Marghidanu <marghidanu@users.noreply.github.com>
Co-authored-by: Tudor Marghidanu <tudor@f2pool.io>
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@rbergen rbergen left a comment

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I always like improvements to one of the original solutions! :)

I have two comments, the second one (array initialization) is the one I think actually matters.

@@ -24,80 +24,66 @@ using namespace std::chrono;
const uint64_t DEFAULT_UPPER_LIMIT = 10'000'000LLU;

class BitArray {
uint32_t *array;
uint8_t *array;
size_t arrSize;
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Is it necessary to declare arrSize as a member variable? It's private so only visible to the BitArray member functions, and I don't think it's used anywhere outside the constructor.

Comment on lines 46 to 47
// Bits are left at zero default, so no need to initialize them
// std::memset(array, 0x00, arraySize(arrSize));
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Are you absolutely sure? When I was learning C++, it was hammered into me by my teacher that with C and C++, one has to assume garbage when allocating memory via new.

I actually looked up the documentation in the C++ reference, and this is what it says about default initialization, which is what's done when new T is used ("if T is an array type, every element of the array is default-initialized", as per Default-initialization):

When storage for an object with automatic or dynamic storage duration is obtained, the object has an indeterminate value.

If no initialization is performed for an object, that object retains an indeterminate value until that value is replaced.

It may work by accident in your office, but it looks to me we can't rely on that happening elsewhere. :)

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davepl commented Oct 20, 2024 via email

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@rbergen rbergen left a comment

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Thanks, LGTM!

@rbergen rbergen merged commit 887109f into drag-race Oct 20, 2024
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@rbergen rbergen deleted the ibmstuff branch October 21, 2024 15:37
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2 participants